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9/2x^2-72=0
Domain of the equation: 2x^2!=0We multiply all the terms by the denominator
x^2!=0/2
x^2!=√0
x!=0
x∈R
-72*2x^2+9=0
Wy multiply elements
-144x^2+9=0
a = -144; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-144)·9
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-144}=\frac{-72}{-288} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-144}=\frac{72}{-288} =-1/4 $
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